How to print only pattern, not a line?

Question

I've got the following shell command:

$ ex +'/>\zs\w\+\ze</p' -scq! /dev/stdin <<<$"foo>bar<buzz"
foo>bar<buzz

however it's matching the whole line, instead of the pattern.

How can I print only the matching pattern (bar)?

Answer 1

try :

ex +'s/.*>\(\w\+\)<.*/\1/|p' -scq! /dev/stdin <<<$"foo>bar<buzz"