10

I've the following sample code which modifies the current line using Python statement:

:py import vim; vim.current.line="["+vim.current.line+"]"

How I can execute this statement for each line in the current file?

Related: How can you use Python in Vim? at stackoverflow

10

You can use the pydo command available since Vim 7.4, the manual describe how it works better than I could:

:[range]pydo {body}

Execute Python function "def _vim_pydo(line, linenr): {body}" for each line in the [range], with the function arguments being set to the text of each line in turn, without a trailing <EOL>, and the current line number. The function should return a string or None. If a string is returned, it becomes the text of the line in the current turn. The default for [range] is the whole file: "1,$".

For your example you can use a command like:

:python import vim
:pydo vim.current.buffer[linenr - 1] = '[%s]' % line

The linenr - 1 bit is there because lines in vim.current.buffer are 0-indexed but Vim start to count lines from 1.

The nice thing is that you can easily define a custom command to execute your Python code on a range of lines:

command! -range=% BracketLines 
    \ <line1>,<line2>pydo vim.current.buffer[linenr - 1] = '[%s]' % line
  • 1
    It's available since vim 7.4. – kenorb Feb 16 '15 at 15:31
7

You can get the current buffer with vim.current.buffer, which is an iterable; you can use use a for loop to get each line.

You can change the lines by assigning to them; so putting that together, we get:

:py from vim import *
:py for i, line in enumerate(current.buffer): current.buffer[i] = '[%s]' % line

Also see :help python-buffer.

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.