Haskell has a literal syntax for anonymous functions of
\pattern0 pattern1 [...] patternN -> expression
which interacts oddly with vim's parenthesis text objects when pattern0 starts with a (.
For example in the line
foldr (\(a,b) c -> a + b * c) 0 [ (0,1), (2,3) ]
^
If my cursor is on the , in (a,b), I'd like the normal mode command di( to delete the a,b and leave the cursor on the ), like so:
foldr (\() c -> a + b * c) 0 [ (0,1), (2,3) ]
^
However, with cpoptions=aABceFs, the \ prevents the ( from matching the ) in \(a,b), so the entire start of the lambda expression is deleted:
foldr () c -> a + b * c) 0 [ (0,1), (2,3) ]
^
With cpoptions=aABceFsM, it's a little better as % works properly, but the entire lambda expression is deleted:
foldr () 0 [ (0,1), (2,3) ]
^
How can I get di( to just delete a,b?
:nnoremap di( vT(Ot)dThe only downside is that this doesn't work withci(,yi(,vi(,da(and the endless variations. – James May 20 '16 at 16:47di(works as desired in newer versions. – rampion May 20 '16 at 17:58