1

I want to essentially be able to use a command similar to dt#, where the # represents any numerical character.

My use case is modifying a script where I have a few server instances with long names that I wanted to abbreviate, from:

instance0
instance1
instance2
instance3

to

i0
i1
i2
i3

Is that possible without a regex? It would be useful to have something similar that includes a way to represent any alpha or symbol too.

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1 Answer 1

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2

Placing your cursor on the second character in your string (n), you could use d/\d.

I suppose this does count as regex still, but looking at the documentation of t and f, they both use {char} which does not seem to include character groups or types such as \d represents digits in a regex pattern.

i[n]stance0
instance1
instance2
instance3

d/\d

i0
instance1
instance2
instance3
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3
  • This looks pretty much what I was thinking of! So d/\d uses a forward search to the next digit character as the motion? vimregex.com/#metacharacters
    – Mike
    Oct 30, 2015 at 10:43
  • 1
    Yup, that is correct!
    – timss
    Oct 30, 2015 at 10:54
  • Then you can use j.j.j.
    – SergioAraujo
    Feb 12, 2018 at 14:59

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