6

I can run this snippit of code within a vimscript block:

0read /home/user/.vim/bundle/vim-lorum/lorums/lorum.js

As expected, it puts the contents of "lorum.js" into the current buffer

But, I need to make this a little more dynamic. If I try something like:

let g:filePath="/home/user/.vim/bundle/vim-lorum/lorums/lorum.js"
0read g:filePath

I get this error message:

E484: Can't open file g:filePath

I tried wrapping g:filePath in expand and glob but I get similar errors. Any ideas?

9

This is because vim does not evaluate variable names or functions with most commands. In your case, vim thinks you literally want to read the contents of a file called g:filePath into the buffer. What you want can be accomplished with the :execute command. This command takes a string as an argument, and will then run that string as a command. In your case, this is how it would look:

:let g:filePath="/home/user/.vim/bundle/vim-lorum/lorums/lorum.js"
:execute "0read " . fnameescape(g:filePath)

The fnameescape part is just to ensure that all special characters are escaped properly (see :help fnameescape()). For more on how to use :execute, read :help :execute. Also note that . is vim's string concatenation operator.

  • Perhaps add a space after 0read? Also wrap g:filePath in a fnameescape()? – Sato Katsura Jul 21 '15 at 17:04
7

The solution to this type of problem is the :execute command:

:execute '0read' g:filepath

See

:help :execute
7

Commands like read don't evaluate your variables, it takes the argument to be a literal (a file named g:filePath). The execute command, however, takes string arguments, concatenates them and executes the result as if it were a command invocation. You can therefore 'wrap' your command: turn the read command into a string and pass is together with the variable as arguments to execute.

:exe "0read" g:filePath
  • I wonder what is the 0 in 0read, the particularities. – Sergio Abreu Jan 6 '17 at 23:57
  • @SergioAbreu read inserts below the cursor, {range}read inserts below the specified line. Using 0 as the {range} inserts at the top of the buffer. – jjaderberg Jan 9 '17 at 12:23
  • And $read to the end :) I got it. Thanks. – Sergio Abreu Jan 9 '17 at 22:12

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