How can I repeat the execution of a macro until a character is encountered?

For example (just an example, it's not the original problem I want you to solve) I want to convert a CAPITAL_CAMEL_CASE to Sentence case in the following line using the macro as follows: ^7wviwu~, now since I have Some_string_constant, I want to replace _ with a (space), for that _ have written another macro f_r<space>.

private static final String SOME_STRING_CONSTANT = "SOME_STRING_CONSTANT";

Now different lines have different number of _ and I need to carefully manually count and repeat the second macro. How can I repeat second macro until I encounter " as I am trying to execute macro only on the string enclosed in "?

Note: I am using a vim plugin in IDE which does not support a replacement for a selection.

  • tpope's abolish plugin has support for changing from cases
    – D. Ben Knoble
    Jul 26, 2021 at 16:05
  • Depends on whether IDE supports vim plugins, which is probably not the case
    – Maxim Kim
    Jul 26, 2021 at 16:27

1 Answer 1


In vim (not sure about other IDE plugins)

  • When there is a "fail" in a macro it stops execution.
  • When f<char> can't find next char it "fails".

So you can

  1. Create a macro @r that does only f_r<space>.
  2. Use it in other macro @q that executes @r with a large count.
  3. Or use it in :normal command if your IDE supports it.


enter image description here

PS, simpler sequences



Normal command:

:'<,'>normal! vi"u~h100@r

where @r is qrf_r q

  • 1
    Another option would be a recursive macro that repeats the f_r step: qrqqrf_r @rq, I think
    – D. Ben Knoble
    Jul 26, 2021 at 16:06
  • Yes indeed. I don't like recursive macros thus didn't even think about them ;)
    – Maxim Kim
    Jul 26, 2021 at 16:28

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