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Is it possible to do this:
function Foo(func_ref) abort
nnoremap <buffer> <cr> :find_a_way_to_call_func_ref
endfunction
function s:callback() abort
echo "123"
endfunction
command Test call Foo(function('s:callback'))
To be clear, :h Funcref is not String, it's type is v:t_func.
It's really doable with execute... and call()
function Foo(func_ref) abort
execute printf('nnoremap <buffer><cr> :call call(%s, [])<CR>',
\ string(get(a:func_ref, 'name')))
endfunction
I don't think it is possible to directly call this funcref from within mapping -- by the time you press mapped key funcref is already disposed/freed/unavailable.
You can try to persist funcref though (either in global or script local dict):
let g:my_funcs={}
function! Foo(func_ref) abort
let g:my_funcs.f = a:func_ref
nnoremap <buffer> <cr> :call g:my_funcs.f()<CR>
endfunction
function! Callback() abort
echom "123"
endfunction
command! Test call Foo(function('Callback'))
It is not necessary to use dictionary, you can have regular global var I think. But for the dictionary you can come up with some clever things, like having array of functions, caching or whatever else.
function(...) including arguments, with a lambda and with a funcref() for a function that has been overwritten. Good job!
Sure, you want to use the execute command, which acts like an eval:
function Foo(func_ref) abort
exe"nnoremap <buffer> <cr> :".func_ref."()<cr>"
endfunction
:help Funcreftalks more about that and mentions lambdas explicitly... What I'm saying is that you might want to clarify your question with an example call of Foo (perhaps with a lambda?) to make it absolutely clear what you're trying to accomplish... As it stands, your question is likely to attract incorrect answers (such as the one withexecute), which might not be the case if you had an example call that would make it clear that wouldn't have worked.Funcref, but you are right, it's still confusing, I clarified it in the update.