How to delete entry from indented argument from list?

Question

Let's say with the cursor I'm on b in

def f(a=1,
      b=2,
      c=3,
      e=4
      )

and we want to delete the whole argument including the line break, so that we get

def f(a=1,
      c=3,
      e=4
      )

but without deleting the preceding character (i.e. it should also be applicable to deleting a...) What is the shortest way to do so?

I'm asking because in non-vim texteditors you could do so by selecting the whole line using shift+down arrow and then deleting the selection using del, and so far I have not found an efficient way to do so in vim, the best I could come up with is using visual mode: v, j, h, d

---

You can also imagine a similar situation with something like

y = a * xa + \
    b * xb + \
    c * xc 

Answer 1

You could do, DJx

D -> delete rest of the line
J -> join the next line
x -> delete the space added by join

Answer 2

the best I could come up with is using visual mode: v, j, h, d

h is needed, because you've set selection=inclusive (this is default). To make the selection behave like in a majority of other text editors use set selection=exclusive.

Next, if you want shift+arrow to start the selection you should set keymodel=startsel.

Also, "delete" normally works the same way as x, so having set the two options above you should be able to do "shift+down+delete" to do the job.

So, as you see, the whole difference is due to the "unusual" default settings.