I posted this question on stackoverflow already, but realized afterwards that it's probably better to ask here.
So I have a function of the following form:
function! s:my_function(dict_arg) let darg = copy(a:dict_arg) func! my_inner_func(cond) if a:cond ==# 'a' execute darg.a elseif a:cond ==# 'b' execute darg.b elseif a:cond ==# 'c' execute darg.c endif endfunc return function('my_inner_func') endfunc
Where the argument passed to the
dict_arg parameter will be some dict keyed with
c, with their respective values being strings representing Ex commands that will be executed depending on the specific
The purpose of the outer function
s:my_function is to generate a Funcref that will execute the appropriate Ex command (
darg.c) based on the
cond, which is itself determined elsewhere by other variables.
So my problem is that I don't know how to reference the local variable
darg defined in the scope of
s:my_function from within
my_inner_func. When the function is called, I get the error
E121: Undefined variable: darg. It also doesn't work (same error) if I don't define the local variable
darg, and instead just try to do
execute a:dict_arg.b for instance.
I can get around it by defining
darg to be global, as in
let g:darg = copy(a:dict_arg), then later doing
execute g:darg.a. But of course, I'd like to avoid that.
In something like Python, this type of lexical scope resolution is automatic. But VimL is well.. VimL. Any help or pointers will be appreciated.