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Search pattern examples 

"0:4.10.5-5.el7"
"0:0.7.7-13.20120626.ov7"
"6:4.14.8-6.po7_3"
  1. How to search and print all occurrences like above patterns where the first number can be any number ranging from 0-9 separated by ":" trailing with any number or alphabet ranging from a-z separated by . or. in vi editor ?

I could search the occurrences of all the patterns starting with any number [0-9] separated by ":" using 

:%s/[0-9]\+\:
  1. how to remove all the occurrences till end of line of each occurrence
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  • This worked for removing all occurrences of any wild character trailing : till end of line :%s/[0-9]:.*//g
    – hellomister
    Mar 22, 2019 at 15:34
  • To replace beginning of each line in the entire file with a specific pattern ==> :%s/^/stringtoreplace/
    – hellomister
    Mar 22, 2019 at 15:40
  • place all pattern test cases on each line enclosed with ```. And add what you want the result to be.
    – 3N4N
    Mar 22, 2019 at 16:21
  • So 1) do you want to match all your examples or what you described as test? If the latter you can use /\d:[0-9a-z\.]\+ if you want to match your examples you'll need to add _- to [0-9a-z\.]. 2) Your second question is not clear: do you want to remove everything after the : in this case you can use :%s/\d\+:\zs[0-9a-z\.]\+//. If you want to remove all the lines matching the previous pattern you can use a global command like :g/\d\+:[0-9a-z-\.]\+/d. Maybe try to clarify your question so that we can answer it precisely.
    – statox
    Mar 22, 2019 at 17:18
  • And 3) If what you said in your comments is what you were looking for, please write an answer with proper formatting.
    – statox
    Mar 22, 2019 at 17:19

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