Ref to :h foldtext() The number of leading dashes depends on the foldlevel. As follow, I think the foldlevel of printf is 1.

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But, you can see as follow, the number of dashes is 2.

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I can't understand why inconsist

2 Answers 2


The documentation does not say how many dashes are there per foldlevel. As can be seen in the source:

txt = NGETTEXT("+-%s%3ld line: ", "+-%s%3ld lines: ", count);
r = alloc((unsigned)(STRLEN(txt)
        + STRLEN(dashes)        /* for %s */
        + 20            /* for %3ld */
        + STRLEN(s)));      /* concatenated */
if (r != NULL)
    sprintf((char *)r, txt, dashes, count);
    len = (int)STRLEN(r);
    STRCAT(r, s);
    /* remove 'foldmarker' and 'commentstring' */
    foldtext_cleanup(r + len);
    rettv->vval.v_string = r;

So you can see, the number of dashes is actually equal to the foldlevel + 1

  • But why foldlevel+1? I feel this is not convenient by default. Nov 1, 2018 at 7:57
  • Why? That is a question I cannot answer. It's what it is Nov 1, 2018 at 7:59

As @Christian Brabandt showed from the source code, the string used for folding has a "+-" at the beginning of the string, resulting in the foldlevel+1 dashes. I can't answer whether this is intentional or a bug. You could open an issue on the vim github if you feel that this is a bug, and you will hopefully receive either justification for the extra dash or the "bug" will be fixed.

If you would like a "fix" for this, you can add the following to your vimrc:

function MyFoldText()
    let line = getline(v:foldstart)
    let sub = substitute(line, '^\s*\|//\s*\|/\*\|\*/\|{{{\d\=', '', 'g')
    let oneLessDash = strpart(string(v:folddashes),1,len(string(v:folddashes))-2)
    let foldlinecount = foldclosedend(v:foldstart) - foldclosed(v:foldstart) + 1
    let lineCount = " " . string(foldlinecount) . " lines: "
    return "+" . oneLessDash . lineCount . sub
set foldtext=MyFoldText()

This will print the same foldtext as before with just one less dash.

P.S. Welcome to the community!

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