Get directory name from CWD (dirname without preceding path)?

Question

Does anyone know how I can get the directory name of the CWD without the preceding path?

I'm trying to build a titlestring like this one:

{cwd_dirname_without_path}/{file_path_relative_to_cwd}

I think %f would suffice for the second part of the title, but the first part seems tricky.

Look up :h ::. and the expand() function
– muru
Jan 31, 2018 at 10:23 — muru, Jan 31, 2018 at 10:23

Christian Brabandt · Accepted Answer · 2018-01-31 10:27:49Z

12

There are several possibilities:

Use an substitute: :echo substitute(getcwd(), '^.*/', '', '') (which basically means, cut off anything from the beginning until the latest /, note this needs to be adjusted on Windows because the \ is path separator there).
Using fnamemodify(), something like this should do it: :echo fnamemodify(getcwd(), ':t') (which basically means, return the tail path of the current working directory).

answered Jan 31, 2018 at 10:27

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Works like a charm! Thanks! I have been struggling with this since your answer to my last question :p
– Rotareti
Jan 31, 2018 at 10:37

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