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I've been struggling with this topic for a little more than i'd like to admit but here it is:

I've set my vim (~/.vimrc) to indent using 4 spaces using

:set expandtab
:set tabstop=4
:set shiftwidth=4

Whenever I want to detete one of these groups I have to remove every one of the spaces. I thought vim would recognize this and remove them all like they were a single tab. Could anyone shed some light?

thks in advance :3

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    Note that there exists another workflow: I prefer to leave vim indent by itself (in C++ it's possible at least). And when I really need to change the indentation manually, I use either << and >> in normal mode, or CTRL-D and CTRL-T in insert mode. In the end, I never need <BS> nor <del> to remove &sw leading space characters. – Luc Hermitte Jan 29 '18 at 12:16
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You may prefer either or both of the following options:

set smarttab
set softtabstop=4

The primary difference between these two options in your case (where expandtab tabstop=4 shiftwidth=4) is whether the "backspace deletes 4 spaces" behavior works only at the beginning of lines (as with smarttab only) or everywhere, aligning to tab stops (as with softtabstop=4). For other values of expandtab, tabstop, shiftwidth the behavior is much more complex.

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2

The other choice is to just use '<<' or '>>' to shift the line left or right. That should give you exactly the behavior you want from anywhere on the line. You can of course delimit a group of lines by moving to an opening or closing '[', '(' or '{', and doing '<%' or '>%' to shift a range of lines.

Of course other movement types work as well:

 >L
 >/foo^M

and others.

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  • 1
    Or you could use ctrl-t and ctrl-d in insert mode. (see :help i_ctrl-t and :help i_ctrl-d) – Octaviour Jan 30 '18 at 17:27
  • Thanks for this tip, @Octaviour! :) – Dee'Kej Nov 11 '19 at 8:36

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