Timeline for Using variable to find & replace while incrementing number with regex
Current License: CC BY-SA 4.0
7 events
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| Jun 2, 2023 at 13:15 | history | edited | D. Ben Knoble♦ | CC BY-SA 4.0 |
added 189 characters in body
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| Jun 2, 2023 at 13:13 | comment | added | D. Ben Knoble♦ |
It's not my answer. But I've pointed out what you need to change. You don't want to put anything after s//\=a/ except the | let a += 1; anything after the slash but before the bar becomes a syntax error. To change the pattern to ` 0 : Container` but change only the 0, write :let a = 1 | g/ \zs0\ze : Container(/s//\=a/ | let a += 1. This is why I recommend trying with just regular search / first, to make sure the pattern works as you want. Then, simply :let a = 1 | g//s//\=a/ | let a += 1. You keep trying to add pattern-ish things outside of where I showed @AdjunctProfessorFalcon
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| Jun 1, 2023 at 22:26 | comment | added | AdjunctProfessorFalcon | Obviously this works to match the pattern: g/ \d : Container( but I can't seem to insert the variable stuff in there. I've tried: let a = 10 | g// \d /s//\=a/ : Container( but then I get error like "misplaced =" | |
| Jun 1, 2023 at 22:23 | comment | added | AdjunctProfessorFalcon | I don't understand your answer because you're just illustrating a solution that's the opposite of what I'm trying to do (which is to understand the correct syntax with the variable usage) if the pattern is inverted. The example you've provided is the same as your other answer to the other post. | |
| Jun 1, 2023 at 22:13 | comment | added | D. Ben Knoble♦ | The command you pasted is the same broken command from your question @AdjunctProfessorFalcon. You need to change the part between the slashes of global if you want to change the matched pattern. (I'm not going to do it for you, because I think it's a good exercise for you at this point.) | |
| Jun 1, 2023 at 19:53 | comment | added | AdjunctProfessorFalcon | Thank you for responding to this! What if the pattern I wanted to match was "0 : Container(" and I wanted to increment the 0? Can I swap around the pattern and do: global/ \zs\d\+\ze,$/ substitute//\=a/ : Container( | let a += 1 | |
| Jun 1, 2023 at 19:49 | history | answered | D. Ben Knoble♦ | CC BY-SA 4.0 |